Posted August 24, 2013
high rated
A riddle before you holds 4 numbers. The key is to find ages of all brothers. Enter them instead of letters a, b, c, d.
The prize is not from this weekend's promo. It is a strategy game. The winner names a game title as a proof of solution.
→ aVHb-YGHJ-STSc-dBFG
Four brothers walk a path together.
The middle brother leads the way,
Two younger twins go in the center.
The elder brother walks the last.
First brother's age is less than 9. Hovewer, 0 it is not.
Two twins together share his age. Remember, 9 can't be split in two.
If elder brother's age was doubled. And middle brother had a twin.
The sum of ages would be equal, between the elder and the rest.
The prize is not from this weekend's promo. It is a strategy game. The winner names a game title as a proof of solution.
→ aVHb-YGHJ-STSc-dBFG
Four brothers walk a path together.
The middle brother leads the way,
Two younger twins go in the center.
The elder brother walks the last.
First brother's age is less than 9. Hovewer, 0 it is not.
Two twins together share his age. Remember, 9 can't be split in two.
If elder brother's age was doubled. And middle brother had a twin.
The sum of ages would be equal, between the elder and the rest.
